Author Topic: Member Spotlight #1 - NekoJonez (Read 536904 times)

NekoJonez · « **Reply #775 on:** June 04, 2012, 04:56:51 PM »

Quote from: NekoBlindshoT on June 04, 2012, 04:55:03 PM

do you know shakespeare?

Yes. But not that much

Noob · « **Reply #776 on:** June 04, 2012, 05:52:38 PM »

How do you like your coffee?
Do you drink tea?
When will we run out of questions?

NekoBot · « **Reply #777 on:** June 04, 2012, 05:55:02 PM »

Its been awhile scince I asked thee a question no? How long has it been exactly?
Should I change my profile picture?

NekoJonez · « **Reply #778 on:** June 04, 2012, 05:59:52 PM »

Quote from: Hi on June 04, 2012, 05:52:38 PM

How do you like your coffee?
Do you drink tea?
When will we run out of questions?

With a bit of milk.
Ice Tea :3
Maybe, it could happen.

Quote from: NekoBot on June 04, 2012, 05:55:02 PM

Its been awhile scince I asked thee a question no? How long has it been exactly?
Should I change my profile picture?

I dunno for sure.
You don't have too of course.

NekoBot · « **Reply #779 on:** June 04, 2012, 06:03:22 PM »

Solve the following problem?

Evaluate $\displaystyle{ \lim_{n \to \infty }\sum_{i=1}^{n} { 3 \Big(1 + {1 \over n }\Big)^2 { 1 \over n } } }$

NekoJonez · « **Reply #780 on:** June 04, 2012, 06:03:58 PM »

Quote from: NekoBot on June 04, 2012, 06:03:22 PM

Solve the following problem?

Evaluate $\displaystyle{ \lim_{n \to \infty }\sum_{i=1}^{n} { 3 \Big(1 + {1 \over n }\Big)^2 { 1 \over n } } }$

* Runs *

NekoBot · « **Reply #781 on:** June 04, 2012, 06:04:53 PM »

Quote from: NekoJonez on June 04, 2012, 06:03:58 PM

Quote from: NekoBot on June 04, 2012, 06:03:22 PM
Solve the following problem?

Evaluate $\displaystyle{ \lim_{n \to \infty }\sum_{i=1}^{n} { 3 \Big(1 + {1 \over n }\Big)^2 { 1 \over n } } }$

* Runs *

You cant run away from calculus my friend. Dost thou remember such intriquite frustrations?

NekoJonez · « **Reply #782 on:** June 04, 2012, 06:05:58 PM »

Quote from: NekoBot on June 04, 2012, 06:04:53 PM

Quote from: NekoJonez on June 04, 2012, 06:03:58 PM
Quote from: NekoBot on June 04, 2012, 06:03:22 PM
Solve the following problem?

Evaluate $\displaystyle{ \lim_{n \to \infty }\sum_{i=1}^{n} { 3 \Big(1 + {1 \over n }\Big)^2 { 1 \over n } } }$

* Runs *

You cant run away from calculus my friend. Dost thou remember such intriquite frustrations?

I sorta dislike math. Especially this sort. T^T

NekoBot · « **Reply #783 on:** June 04, 2012, 06:07:01 PM »

Quote from: NekoJonez on June 04, 2012, 06:05:58 PM

Quote from: NekoBot on June 04, 2012, 06:04:53 PM
Quote from: NekoJonez on June 04, 2012, 06:03:58 PM
Quote from: NekoBot on June 04, 2012, 06:03:22 PM
Solve the following problem?

Evaluate $\displaystyle{ \lim_{n \to \infty }\sum_{i=1}^{n} { 3 \Big(1 + {1 \over n }\Big)^2 { 1 \over n } } }$

* Runs *

You cant run away from calculus my friend. Dost thou remember such intriquite frustrations?
I sorta dislike math. Especially this sort. T^T

$\displaystyle{ \lim_{n \to \infty }\sum_{i=1}^{n} { 3 \Big(1 + {i \over n }\Bi......_{n \to \infty }\sum_{i=1}^{n} { { 3 \over n } \Big(1 + {i \over n }\Big)^2 } }$

$= \displaystyle{ \lim_{n \to \infty } { 3 \over n } \sum_{i=1}^{n}\Big\{ 1 + { 2i \over n } + { i^2 \over n^2 } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } { 3 \over n } \Big\{ \sum_{i=1}^{n} 1+ \sum_{i=1}^{n} { 2i \over n } + \sum_{i=1}^{n} { i^2 \over n^2 } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } { 3 \over n } \Big\{ \sum_{i=1}^{n} 1......um_{i=1}^{n} i \Big) + { 1 \over n^2 } \Big( \sum_{i=1}^{n} i^2 \Big) \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } { 3 \over n } \Big\{ (1)(n)+ { 2 \over n } { n(n+1) \over 2 } + { 1 \over n^2 } { n(n+1)(2n+1) \over 6 } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } { 3 \over n } \Big\{ n+ (n+1) + { (n+1)(2n+1) \over 6n } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } { 3 \over n } \Big\{ 2n+ 1 + { 2n^2 + 3n + 1 \over 6n } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } \Big\{ 6 +{ 3 \over n } + { 6n^2 + 9n + 3 \over 6n^2 } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } \Big\{ 6 +{ 3 \over n } + { 6n^2 \over 6n^2 } + { 9n \over 6n^2 } + { 3 \over 6n^2 } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } \Big\{ 6 +{ 3 \over n } + 1 + { 3 \over 2n } + { 3 \over 6n^2 } \Big\} }$ (Now evaluate the limit.) = 6 + (0) + 1 + (0) + (0) = 7 .

Theres the solution. Nice right?

NekoJonez · « **Reply #784 on:** June 04, 2012, 06:07:29 PM »

Quote from: NekoBot on June 04, 2012, 06:07:01 PM

Quote from: NekoJonez on June 04, 2012, 06:05:58 PM
Quote from: NekoBot on June 04, 2012, 06:04:53 PM
Quote from: NekoJonez on June 04, 2012, 06:03:58 PM
Quote from: NekoBot on June 04, 2012, 06:03:22 PM
Solve the following problem?

Evaluate $\displaystyle{ \lim_{n \to \infty }\sum_{i=1}^{n} { 3 \Big(1 + {1 \over n }\Big)^2 { 1 \over n } } }$

* Runs *

You cant run away from calculus my friend. Dost thou remember such intriquite frustrations?
I sorta dislike math. Especially this sort. T^T

$\displaystyle{ \lim_{n \to \infty }\sum_{i=1}^{n} { 3 \Big(1 + {i \over n }\Bi......_{n \to \infty }\sum_{i=1}^{n} { { 3 \over n } \Big(1 + {i \over n }\Big)^2 } }$
$= \displaystyle{ \lim_{n \to \infty } { 3 \over n } \sum_{i=1}^{n}\Big\{ 1 + { 2i \over n } + { i^2 \over n^2 } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } { 3 \over n } \Big\{ \sum_{i=1}^{n} 1+ \sum_{i=1}^{n} { 2i \over n } + \sum_{i=1}^{n} { i^2 \over n^2 } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } { 3 \over n } \Big\{ \sum_{i=1}^{n} 1......um_{i=1}^{n} i \Big) + { 1 \over n^2 } \Big( \sum_{i=1}^{n} i^2 \Big) \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } { 3 \over n } \Big\{ (1)(n)+ { 2 \over n } { n(n+1) \over 2 } + { 1 \over n^2 } { n(n+1)(2n+1) \over 6 } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } { 3 \over n } \Big\{ n+ (n+1) + { (n+1)(2n+1) \over 6n } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } { 3 \over n } \Big\{ 2n+ 1 + { 2n^2 + 3n + 1 \over 6n } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } \Big\{ 6 +{ 3 \over n } + { 6n^2 + 9n + 3 \over 6n^2 } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } \Big\{ 6 +{ 3 \over n } + { 6n^2 \over 6n^2 } + { 9n \over 6n^2 } + { 3 \over 6n^2 } \Big\} }$ $= \displaystyle{ \lim_{n \to \infty } \Big\{ 6 +{ 3 \over n } + 1 + { 3 \over 2n } + { 3 \over 6n^2 } \Big\} }$ (Now evaluate the limit.) = 6 + (0) + 1 + (0) + (0) = 7 .

Theres the solution. Nice right?

* Brain just went boom . *

NekoBot · « **Reply #785 on:** June 04, 2012, 06:09:21 PM »

Answer this one?

Besides 10 and 1, what is one factor of 10?

NekoJonez · « **Reply #786 on:** June 04, 2012, 06:11:19 PM »

Quote from: NekoBot on June 04, 2012, 06:09:21 PM

Answer this one?

Besides 10 and 1, what is one factor of 10?

T^T Stop torturing me ....

NekoBot · « **Reply #787 on:** June 04, 2012, 06:13:54 PM »

Quote from: NekoJonez on June 04, 2012, 06:11:19 PM

Quote from: NekoBot on June 04, 2012, 06:09:21 PM
Answer this one?

Besides 10 and 1, what is one factor of 10?

T^T Stop torturing me ....

Do you need some medical atention?

NekoJonez · « **Reply #788 on:** June 04, 2012, 06:16:51 PM »

Quote from: NekoBot on June 04, 2012, 06:13:54 PM

Quote from: NekoJonez on June 04, 2012, 06:11:19 PM
Quote from: NekoBot on June 04, 2012, 06:09:21 PM
Answer this one?

Besides 10 and 1, what is one factor of 10?

T^T Stop torturing me ....

Do you need some medical atention?

Is there a doctor is the room

NekoBot · « **Reply #789 on:** June 04, 2012, 06:25:33 PM »

Im afraid we are in the middle of a barren waistland, the only water anywhere for miles is in my right hand. There are no doctors for at least 70 kilometers, What do you do?

NekoJonez · « **Reply #790 on:** June 04, 2012, 06:26:44 PM »

Quote from: NekoBot on June 04, 2012, 06:25:33 PM

Im afraid we are in the middle of a barren waistland, the only water anywhere for miles is in my right hand. There are no doctors for at least 70 kilometers, What do you do?

Try to wake up. Or just accepting my fate and hope to survive.

NekoBot · « **Reply #791 on:** June 04, 2012, 06:28:30 PM »

What if by some miracle that a helicopter flies by and you have the oppertunity to get away but te cost is to solve one calculus problem. What would you do then?

NekoJonez · « **Reply #792 on:** June 04, 2012, 06:29:10 PM »

Quote from: NekoBot on June 04, 2012, 06:28:30 PM

What if by some miracle that a helicopter flies by and you have the oppertunity to get away but te cost is to solve one calculus problem. What would you do then?

(If you dare to post one

)

Well... Try to solve it the best I can.

NekoBot · « **Reply #793 on:** June 04, 2012, 06:30:36 PM »

Quote from: NekoJonez on June 04, 2012, 06:29:10 PM

Quote from: NekoBot on June 04, 2012, 06:28:30 PM
What if by some miracle that a helicopter flies by and you have the oppertunity to get away but te cost is to solve one calculus problem. What would you do then?
(If you dare to post one )

Well... Try to solve it the best I can.

(would you ban me? XD)

What if by some chance you got it right. But I got it wrong, what thwen?

NekoJonez · « **Reply #794 on:** June 04, 2012, 06:31:44 PM »

Quote from: NekoBot on June 04, 2012, 06:30:36 PM

Quote from: NekoJonez on June 04, 2012, 06:29:10 PM
Quote from: NekoBot on June 04, 2012, 06:28:30 PM
What if by some miracle that a helicopter flies by and you have the oppertunity to get away but te cost is to solve one calculus problem. What would you do then?
(If you dare to post one )

Well... Try to solve it the best I can.

(would you ban me? XD)

What if by some chance you got it right. But I got it wrong, what thwen?

Well... If I am wrong... I enter the helicopter by force.